20+15=/35-45
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Answer:
i) Mean = 1933.1817
ii) Range = 5684
iii) Third quartile = 6054
Step-by-step explanation:
Given data :
currency exchange rate : 1 AUD = 5.8 HKD
cost of each ounce = 2 AUD
Fixed shipping cost for each carton = 80 HKD
number of cartons = 20
next determine the total cost of the 20 cartons in HKD
= ∑(weight in ounce * cost of each ounce *exchange rate) +fixed shipping cost
= ∑ ( 160*2*5.8 + 80 ) + -------------- + (650 *2*5.8 + 80 ) ----------------- ( 1 )
= 81756 HKD
<u>i) find the mean value ( X ) </u>
= Total cost / number of cartons
= 81756 / 20 = 4087.8
ii) Find the standard deviation
= note: std = √∑(xi-X )^2 / (n-1)
= 1933.1817
<u>iii) Find the range </u>
Range = highest cost - lowest cost ( values gotten from equation 1 )
= 7650 - 1936
= 5684
<u>iv) Determine the third quartile </u>
third quartile = 6054
<em>attached below is the detailed solution</em>
Word form is
sixty-seven and nine hundred forty-three thousandths
Hope this helps :3
Answer:
6) x^2+6x+8
7) x^2+3x-10
Step-by-step explanation: