Step-by-step explanation:
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Answer:
-90
Step-by-step explanation:
Once the cake is removed from the oven, it has been exposed to the room temperature of 70°F. After 10 minutes, the cake's temperature decreased to 200°F, which is 150°F cooler than it initially was (350°F). As for the what is asked, 90°F is 260°F cooler than its original temperature (350°F).
This problem can be expressed in a ratio:
10mins:150<span>°F = N:260</span><span>°F
where N is how long it will take for</span><span> cake to cool to 90°F
</span>150<span>°FxN=10x260
</span>150N=2600
N=2600/150
N=17.33
N<span>≈20 minutes
Thus, it takes approximately 20 minutes </span><span>for the cake to cool to 90°F</span>
-1 + 10 = 9 +10 = 19 + 10 = 29 so the next would be 39 because you add ten to it and there is only one answer with 39 so it's C
<span>r^2 = 529 - 46x + x^2 + 64
r^2 = x^2 - 46x + 593
replace r^2 with (x^2+ 225)
x^2 + 225 = x^2 - 46x + 593
x^2 - x^2 + 46x = 593 - 225
46x = 368
x = 368/46
x = 8 cm
Find the radius
r^2 = 8^2 + 225
r^2 = 289
r =
r = 17 cm is the radius</span>
