Answer:
b = 7, c = -3 and a = 1
Step-by-step explanation:
So I'm assuming you know the quadratic formula, x=-b +- root (b^2-4ac)/2a
so knowing this, it is given that b^2 - 4ac = 61
it is also given 2a = 2 (the bottom of the fraction) which means a =1
and the -b = -7 (the start of the expression), which means b = 7
now we have b = 7, and a = 1
now we can sub it into b^2 - 4 x a x c = 61
b^2 is 7 x 7 = 49
4 x a x c = 4c
so we have 49-4c=61
-4c = 61-49
-4c = 12
c = -3
therefore we have b = 7, c = -3 and a = 1
