C since 25ab and 5ba both have the terms "a" and "b"
I hope this helps you
(1-cosx)(1+cosx)=1+cosx-cosx-cos²x=1-cos²x=sin²x
sin²x
____
cos²x
tg²x
Answer:
a = 10, b = -12
Step-by-step explanation:
4+2(5x-8) = ax +b
4 + 10x - 16 = ax + b
10x - 12 = ax + b
Infinitely many solutions when:
a = 10
b = -12
Answer:
Option C is right.
Step-by-step explanation:
Given is a graph with two triangles marked on it.
Triangle ABC is in the I quadrant with vertices (2,2) (2,10) and (8,12)
Triange A'B'C' is in the III quadrant with vertices (-1,-1), (-1,-5) and (-4,-6)
On comparison we find corresponding side of AB is A'B'
Length of AB = 8 and Length of A'B' = 4.
Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.
Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin. The degree of rotation is 180 degrees.
Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees
