3X+7=X+25 SOLVE FOR X. A.9 B.25 C.34 68.
2 answers:
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Answer:
Area(A)=Area(C)=
Area(B)=
Step-by-step explanation:
We begin with finding the angles a and b that from the drawing attached you can see that a=b.
Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:
120+120+a+b=360
240+2a=360
2a=120
a=60=b
Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.
We can say from the drawing as well:
Area(A)+Area(B)+Area(C)=Area(rhomboid)
But, we can also say that Area(A)=Area(C)
So, starting with Area(A)
Area(A)=Area(triangle)==
=
We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.
Area(B)=Area(rhomboid)-Area(A)-Area(C)
Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.
The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.
Area(rhomboid)=5.20*6=
Area(B)=Area(rhomboid)-Area(A)-Area(C)=-
-
=
Answer:
89.1° or -1.4°
Step-by-step explanation:
1. Location:
You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.
The French troops are about 50 m below you and 1.2 km distant.
2. Finding the firing angle
Data:
R = 1200 m
u = 600 m/s
h = -50 m (the height of the target)
a = 9.8 m/s²
We have two conditions.
Horizontal distance
(1) 1200 = 600t cosθ
Vertical distance
(2) -50 = 600t sinθ - 4.9t²
Divide each side of (1) by 600cosθ.
Substitute (3) into (2)
Recall that
(5) sec²θ = 1/cos²θ = tan²θ + 1
Substitute (5) into (4)
Set up a quadratic equation
Solve for θ
Use the quadratic formula.
tanθ = 61.249 or -0.025
θ = arctan(61.249) = 89.1° or
θ = arctan(-0.025) = -1.4°