Step-by-step explanation:
Given
for first circle, center is at
and radius is
units
General equation of circle with center (h,k) and radius r units is given by
![\Rightarrow (x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
for the given circle it is
![\Rightarrow (x-3)^2+(y-2)^2=2^2\\\Rightarrow (x-3)^2+(y-2)^2=4](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-3%29%5E2%2B%28y-2%29%5E2%3D2%5E2%5C%5C%5CRightarrow%20%28x-3%29%5E2%2B%28y-2%29%5E2%3D4)
for second circle center is at (0,-1) and radius is 3 units
Equation is given by
![\Rightarrow (x-0)^2+(y+1)^2=3^2\\\Rightarrow (x-0)^2+(y+1)^2=9](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-0%29%5E2%2B%28y%2B1%29%5E2%3D3%5E2%5C%5C%5CRightarrow%20%28x-0%29%5E2%2B%28y%2B1%29%5E2%3D9)
There are no feasible solutions for minimum and maximum values for the function z = 2x + 4y that follow the given constraints.
- The given constraints are.
- 4x + y ≤ 40
- 20x +y ≥72
- 4x + 5y ≥ 72
- We change these inequalities to equations.
- 4x + y = 40
- 20x +y =72
- 4x + 5y = 72.
- Now we find the points which satisfy the equation when x is 0 and when y is 0. We do this for every equation.
- (0, 40) and (10, 0) satisfy the first equation.
- (0, 72) and (3.6, 0) satisfy the second equation.
- (0, 14.4) and (18, 0) satisfy the third equation.
- Now we plot these equations on the graph.
- Now we shade the regions that belong to the corresponding inequalities.
- The common region contains our feasible solution.
- But here we have no common region for all three inequalities.
- So, there are no feasible solutions.
To learn more about equations, visit :
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the simplest fraction is: 3/5
in decimal form its: 0.6
Answer: Is there a total for how many kids like each? If there isn't than this is how I would solve it. For percentage purposes let's say there are 100 students. 50 like math, 50 like science. Half of the students who like math also like science, which means 75 percent of the school likes science. A third of students who like science also like math, and since 75 percent of the school of 100 children likes science, that would mean 1/3 of that is 25, which would mean 75 percentof all students like math. Hence the ratio, I believe, is 1 to 1.
Step-by-step explanation:
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