The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.
Step-by-step explanation:
The given is,
Given diagram is combination of Rectangle and Semi circle.
Step:1
Res the attachment,
Area of given diagram = Area of A + Area of B..............(1)
Step:2
For A,
The A section in the given diagram is semi circle,
Diameter of semi circle = Total distance - ( 2+3)
( ∵ 2, 3 are top distance in the given diagram)

Diameter, d = 5 cm
Radius, 

r = 2.5 cm
Area,
........................(2)


Step:3
For B,
Area of rectangle is,
.....................(3)
Where, l - Length = 10 cm
b - Width = 2 cm
Equation (3) become,


Area of B,
= 20 
Step:4
From the equation (1),
Area of given diagram = 20+ 9.81747
Area = 29.817 square centimeters
Result:
The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.
Answer:
B. CSCX= sinx / 1
D. tanx=
sin x / COS x
Step-by-step explanation:
A. sec x= 1/cos(x)
CSC X / 1 = sin(x)
B. CSCX
sinx / 1 = csc(x)
C. tanx= sin(x) / cos(x)
secx = 1 / cos(x)
D. tanx= sin(x) / cos (x)
sin (x) / cos(x)
Explanation:
Let us divide the quadrilateral formed by
A
(
6
,
5
)
,
B
(
2
,
−
4
)
,
C
(
−
5
,
2
)
and
D
(
−
3
,
6
)
in two parts,
Δ
A
B
C
and
Δ
A
C
D
.
Now let us find the lengths of their sides.
A
B
=
√
(
2
−
6
)
2
+
(
−
4
−
5
)
2
=
√
16
+
81
=
√
97
=
9.8489
B
C
=
√
(
−
5
−
2
)
2
+
(
2
+
4
)
2
=
√
49
+
36
=
√
85
=
9.2195
A
C
=
√
(
−
5
−
6
)
2
+
(
2
−
5
)
2
=
√
121
+
9
=
√
130
=
11.4018
Now as
s
1
=
1
2
(
9.8489
+
9.2195
+
11.4018
)
=
1
2
×
30.4702
=
15.2351
And area of
Δ
A
B
C
=
√
15.2351
(
15.2351
−
9.8489
)
(
15.2351
−
9.2195
)
(
15.2351
−
11.4018
)
=
√
15.2351
×
5.3862
×
6.0156
×
3.8333
=
√
1892.2545
=
43.5
A
D
=
√
(
−
3
−
6
)
2
+
(
6
−
5
)
2
=
√
81
+
1
=
√
82
=
9.0554
C
D
=
√
(
−
5
+
3
)
2
+
(
2
−
6
)
2
=
√
4
+
16
=
√
20
=
4.4721
s
2
=
1
2
(
9.0554
+
4.4721
+
11.4018
)
=
1
2
×
24.9293
=
12.4647
And area of
Δ
A
C
D
=
√
12.4647
(
12.4647
−
9.0554
)
(
12.4647
−
4.4721
)
(
12.4647
−
11.4018
)
=
√
12.4647
×
3.4093
×
7.9926
×
1.0636
=
√
361.2547
=
19.01
Hence area of quadrilateral
A
B
C
D
is
43.5
+
19.0
=
62.5
units.
Answer: x = k-c/8
Step-by-step explanation:
APEX
Answer:
5pt=2cups
1qt.=2pt
Step-by-step explanation:
I hope that's right