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EastWind [94]
3 years ago
14

Is 9 percent greater then 0.4

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0
Yes 9 percent is greater than 0.4 because when you convert 0.4 to percent, it would be 4 percent.
jeyben [28]3 years ago
4 0
Yes 9 percent is bigger than 0.4 beacsue 0.4 as a precentage would be 4 percent
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A theater company charges $9.50 per ticket for people of all age groups. If c represents the total number of children who bought
professor190 [17]

Answer:

2

Step-by-step explanation:

because whether a child or an adult buys the ticket it is still $9.50

4 0
2 years ago
31 cars are in a race. In how many different ways can cars finish in order in the top 4 positions?
cupoosta [38]

Answer:

755,160 ways

Explanation:

We're told that 31 cars are in a race.

Considering the order in which the cars can finish in the top 4 positions, any of the 31 cars can finish in the first position, any of the remaining 30 cars can finish in the second position, any of the remaining 29 cars can finish in the third position and any of the remaining 28 cars can finish in the fourth position, so the different numbers of ways can be determined as seen below;

31\times30\times29\times28=755,160\text{ ways}

8 0
1 year ago
what number should be added to the expression x squared+2x to change it into a perfect square trinomial?
Nookie1986 [14]
You know that a perfect square trinomial is given by square of first term, twice the product of first and last terms and square of second term

So we have x^2 that is square of x, 2x that is twice the product of x*1, the second term shoulf be 1, that is square of 1

So your answer would be 1

If you try (x+1)^2 = x^2+2x+1
3 0
3 years ago
Read 2 more answers
You roll a pair of fair dice until you roll “doubles” (i.e., both dice are the same). what is the expected number, e[n], of roll
bonufazy [111]

We need to define our outcomes and events.

 

Finding the probability<span> of each event occurring separately, and then multiplying the probabilities is the step to <span>finding  the probability</span> of two independent events that occur in sequence.

</span>

<span>
To solve this problem, we take note of this:</span>

 

The roll of the two dice are denoted by the pair

(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }

Each pair is an outcome. There are 36 pairs and each has probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the number of rolls N until we observe doubles is a geometric (p) random variable and has expected value E[N] = 1/p = 6.

3 0
3 years ago
Which of the following are possible solutions for the inequality ??
meriva
-1/2 and -2 would be the answer

This would be because when you plug these number instead of x the answer is equal to or less than 13
8 0
2 years ago
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