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miv72 [106K]
3 years ago
10

Factor each expression. (GCF) 1. 2xy3 – 10x

Mathematics
1 answer:
Anarel [89]3 years ago
5 0

Answer:

Step-by-step explanation:

Factor: 15x3y2 + 10x2y4   hop                  

ppppppppppppppplllllleeeeaaaasssssseeee brain least

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19810 rounded to the nearest hundred
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19,810 rounded to the nearest hundred is 19,800.
8 is in the hundreds place, and the number 1 is in front of it.
 
Numbers 1-4 in front of the number make the number stay the same.

Numbers 5-9 in front of the number make the numbers round up one number.
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3 years ago
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alexira [117]

Answer:

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3 0
4 years ago
Pls help ill give brainliest lolz​
Nonamiya [84]

Answer:

t =5

Step-by-step explanation:

-7(2-t)=21

-14+7t=21

7t=35

t=5

5 0
2 years ago
Find the present value of an annuity due that pays $4000 at the beginning of each quarter for the next 7 years. Assume that mone
Jlenok [28]

Answer:

Step-by-step explanation:

From the first question:

We are to find PV of the annuity.

Using the formula:

Present value of Annuity  = Annuity Amount × Present Value Annuity Factor i.e. PVAF (n , r)

Where , Annuity Amount = $4,000            

n = No. of periods = 7 years × 4 quarters per year = 28 periods but since the first payment is at beginning of the quarter, Then, n = 27 when considered for PVAF

r  = 6.2% / 4 quarters = 1.55%,

PVAF(n0,r) when first payment is at beginning of n i.e. n0 = 1 + { [1-(1+r)^ -n0 ]/r }

= 1 + { [1-(1+0.0155)^ {-27}]/0.0155 }

= 1 + [ (1 - 0.66015 ) ] / 0.0155]

= 1 + 21.926

= 22.926

PVAF(28,1.55%) = 22.926

Thus , Present Value of Annuity = $4,000 × 22.926  = $91704.00

2. Present value of Annuity due = Annuity Amount × Present Value Annuity Factor i.e. PVAF (n , r)

Present Value of Annuity  = $90,000

n = No. of periods = 7.5 years × 4 quarters per year = 30 periods

r  = 5.4% / 4 quarters = 1.35%,

PVAF(n,r) = [1-(1+r)^-n]/r

PVAF(n,r) = [1-(1+0.0135)^ -30]/0.0135

PVAF(30,1.35%) = (1 - 0.6688)/0.0135

PVAF(30,1.35%) = 0.3312/0.0135

PVAF(30,1.35%) = 24.53

Hence ;

$90,000 = Annuity Amount × 24.53

Annuity amount = $90,000/24.53 = $3,668.48

3 0
3 years ago
An exponential function f(x)
natka813 [3]

Given:

An exponential function f(x)=ab^x passes through the points (0, 12000) and (2, 3000).

To find:

The values of a and b.

Solution:

We have,

f(x)=ab^x      ...(i)

It passes through the point (0,12000). Putting x=0 and f(x)=12000 in (i), we get

12000=ab^0

12000=a(1)

12000=a

Given function passes through the point (2,3000). Putting x=2, a=12000 and f(x)=3000 in (i), we get

3000=12000b^2

\dfrac{3000}{12000}=b^2

\dfrac{1}{4}=b^2

Taking square root on both sides.

\pm \dfrac{1}{2}=b

For an exponential function b cannot be negative. So, b=\dfrac{1}{2}.

Therefore, the value of a is 12000 and the value of b is \dfrac{1}{2}.

3 0
3 years ago
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