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3 years ago

Solve for the value of x

Mathematics

1 answer:

jeka943 years ago

7 0

Answer:

x = -5

Step-by-step explanation:

x + 115 = 110, they are acute to each other

∴ x = 110 - 115

x = -5

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Inflation Rate Suppose the annual rate of inflation averages 2% over the next 10 years. With this rate of inflation, the approxi

alexandr1967 [171]

Answer:

After 10 years the cost will be $ 97.52.

Step-by-step explanation:

This problem requires us to calculate the cost of graphing after 10 years if inflation rate is two percent. This can easily be calculated by compounding present value of current cost at the rate of 2%. Detail calculation is given below.

FV= 80 (1+2%)^10

FV = $ 97.52

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3 years ago

Which expression is equivalent to 5 x + 10 y minus 15?

BlackZzzverrR [31]

Answer:

Step-by-step explanation

5*x=5x -----5*2=10------5*3=15

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4 years ago

Graphing a line given its slope and y-intercept

kifflom [539]

Answer:

see below for a graph

Step-by-step explanation:

One point can be plotted at the y-intercept: (0, -2). Since the slope tells you the line drops 3 units for each 2 units to the right, the point (2, -5) will be another point on the line. The graph will go through those two points.

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4 years ago

The probability that a lab specimen contains high levels of contamination is 0.14. A group of 4 independent samples are checked.

Shtirlitz [24]

Answer:

a) 0.5470 = 54.70% probability that none contain high levels of contamination.

b) 0.3562 = 35.62% probability that exactly one contains high levels of contamination.

c) 0.4530 = 45.30% probability that at least one contains high levels of contamination.

Step-by-step explanation:

For each sample, there are only two possible outcomes. Either they contain high levels of contamination, or they do not. The samples are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a lab specimen contains high levels of contamination is 0.14.

This means that $p = 0.14$

A group of 4 independent samples are checked.

This means that $n = 4$

(a) What is the probability that none contain high levels of contamination?

This is P(X = 0)

$P(X = 0) = C_{4,0}.(0.14)^{0}.(0.86)^{4} = 0.5470$

0.5470 = 54.70% probability that none contain high levels of contamination.

(b) What is the probability that exactly one contains high levels of contamination?

This is P(X = 1)

$P(X = 1) = C_{4,1}.(0.14)^{1}.(0.86)^{3} = 0.3562$

0.3562 = 35.62% probability that exactly one contains high levels of contamination.

(c) What is the probability that at least one contains high levels of contamination?

Either none of the samples contain high levels of contamination, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.5470 = 0.4530$

0.4530 = 45.30% probability that at least one contains high levels of contamination.

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3 years ago

Mr. Baker sells boxes of votive candles to stores. He also has a customer who places a fixed order for designer candles every mo

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This is the answer to the question.

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4 years ago