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3 years ago

What is the proportionality of 4 and 1.50?

Mathematics

1 answer:

Llana [10]3 years ago

5 0

Answer:

y = 0.375x

Step-by-step explanation:

Let there are two variables, one independent variable x and another dependent variable y which are in proportionality relation.

So, y ∝ x

⇒ y = kx ........... (1) {Where k is the proportionality constant}

Let us assume that the given values of 4 and 1.50 are values of x and y respectively.

Hence, from equation (1) we get, 1.5 = 4k

⇒ k = 0.375

So, the proportionality equation is y = 0.375x (Answer)

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What is the value of the expression (36 1/2)^2

Korolek [52]

324 is the answer to your promblem welcome

4 0

2 years ago

-3(x + 4) = (-x - 1)

zaharov [31]

Answer:

x=-5.5

Step-by-step explanation:

-3(x+4)=(-x-1)

1. Distribute

-3x+(-12)=-x-1

2. Simplify

-3x-12=-x-1

-2x-12=-1

-2x=11

x=-11/2

x=-5.5

4 0

3 years ago

Read 2 more answers

Find the value of x ?

enyata [817]

Answer:

Step-by-step explanation:

∠E = ∠G

∠D= ∠F because it’s a parallelogram ==> D=F=2x+12 and E=G=5x

5x+2x+12=180

7x=168

X=24

Solution 2:

2*5x+2*(2x+12)=360

10x+4x+24=360

14x=360-24=336

X=336/14

X=24

4 0

3 years ago

Read 2 more answers

Please answer quickly<br>expand and simplify: 4(5x-3y) (x-4y) -(3x-4y)(2x+3y)

Gekata [30.6K]

Answer: 14x^2-93xy+60y^2 Hope that helps!

Step-by-step explanation:

1. Expand by distributing terms

(20x-12y)(x-4y)-(3x-4y)(2x+3y)

2. Use the Foil method:(a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(3x-4y)(2x+3y)

3. Use the Foil method : (a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(6x^2+9xy-8yx-12y^2)

4. Remove parentheses 20x^2-80xy-12yx+48y^2-6x^2-9xy+ 8yx+12y^2

5. Collect like terms (20x^2-6x^2)+(-80xy-12xy-9xy+8xy)+(48y^2+12y^2)

6. Simplify.

And your answer would be 14x^2-93xy+60y^2

5 0

2 years ago

7 + 2y = 8x 3x - 2y = 0 Solve the system of equations by substitution. (70/3, 140/9) (7/5, 21/10) no solution coincident

Wittaler [7]

So we have the system of equations:
$7+2y=8x$ equation (1)
$3x-2y=0$ equation (2)

To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for $x$ in equation (2):
$3x-2y=0$
$3x=2y$
$x= \frac{2}{3}y$ equation (3)

Replacing equation (3) in equation (1):
$7+2y=8x$
$7+2y=8( \frac{2}{3} y)$
$7+2y= \frac{16}{3} y$
$7= \frac{10}{3} y$
$y= \frac{7}{ \frac{10}{3} }$
$y= \frac{21}{10}$ equation (4)

Replacing equation (4) in equation (3):
$x= \frac{2}{3}y$
$x=( \frac{2}{3} )( \frac{21}{10} )$
$x= \frac{7}{5}$

We can conclude that the solution of our system of equations is <span>(7/5, 21/10)</span>

5 0

3 years ago