Answer:
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Step-by-step explanation:
Answer:
The number of boxes of candy sold is 4
The number of rolls of wrapping paper sold is 10
Step-by-step explanation:
Let x = number of boxes of candy that was sold.
Let y = number of rolls of wrapping paper was sold.
The candy sells for 8 dollars per box and the wrapping paper sells for 6 dollars per roll. This means that x boxes of candy and y rolls of wrapping paper will be sold for
$(8x + 6y)
If you have sold 14 items, and collected 92 dollars, this means that
x + y = 14
8x + 6y = 92 - - - - - - -1
Substituting x = 14 - y into equation 1, it becomes
8(14-y) + 6y = 92
112 - 8y + 6y = 92
- 8y + 6y = 92 - 112
-2y = -20
y = 20/2 = 10
x = 14 - y
x = 14 - 10
x = 4
The number of boxes of candy sold is 4.
The number of rolls of wrapping paper sold is 10.
Answer:
Amount invested at 7% = 16000
Amount invested at 9% = 12000
Step-by-step explanation:
Let x be the amount invested at 7% and y be the amount invested at 9%.
Since the total amount invested is $28000, therefore, we can set up the first equation as:

Secondly, we are give that sum of two investments is $2200. Therefore, we can write the second equation as:

Now we need to solve these two equations to get the values of x and y.
First of all, we multiply the second equation with 100 in order to get rid of decimal values.

Let us use substitution method here. First of all we will solve for y from first equation and plug that into second equation.


Therefore, amount invested at 7% is $16000 and amount invested at 9% is 28000-16000=$12000.
Answer:
v = 1.8 x 10^6
Step-by-step explanation:
v= π r 2h
/3