1. 343x³ - 8 = 0
343x³ + 98x² - 98x² + 28x - 28x - 8 = 0
343x³ + 98x² + 28x - 98x² - 28x - 8 = 0
7x(49x²) + 7x(14x) + 7x(4) - 2(49x²) - 2(14x) - 2(4) = 0
7x(49x² + 14x + 4) - 2(49x² + 14x + 4) = 0
(7x - 2)(49x² + 14x + 4) = 0
7x - 2 = 0 or 49x² + 14x + 4 = 0
+ 2 + 2 x = -(14) ± √((14)² - 4(49)(4))
7x = 2 2(49)
7 7 x = -14 ± √(196 - 784)
x = ²/₇ 98
x = -14 ± √(-588)
-98
x = -14 ± 14i√(3)
-98
x = -14 + 14i√(3) or x = -14 - 14i√(3)
-98 -98
x = ¹/₇ - ¹/₇i√(3) or x = ¹/₇ + ¹/₇√(3)
x = ¹/₇ ± ¹/₇i√(3)
Solution Set: {¹/₇ ± ¹/₇i√(3), ²/₇}
2. 64x³ = 0
64 64
x³ = 0
∛(x³) = ∛(0)
x = 0
Solution Set: {0}
This is easy, add 58.3 and 12.08 together, 70.38
subtract 9.4 from 70.38
60.98
the answer is 60.98
The answer is 700 all you have to do is do 350 + 350
Answer:
f(0) = 243 . . . cats at the start
Step-by-step explanation:
The exponential function tells you the number of cats after t years is ...
f(t) = 243(1/3)^t
When t=0, the exponential factor is 1, so the value of the function is the multiplying constant.
f(0) = 243
This means there were 243 stray cats in town when the animal control program started.
Answer:
11.1
Step-by-step explanation:
Use the Pythagorean Theorem to find the side.
