Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
Answer:
see below
Step-by-step explanation:
In the attachment, the points are listed in the order given in the problem statement. (They are listed to the right of the "rotation matrix", with x-coordinates above y-coordinates.)
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I really don't like to do repetitive calculations, so I try to use a graphing calculator or spreadsheet whenever possible. Angles are measured CCW.
As always, the rotation transformations are ...
180° — (x, y) ⇒ (-x, -y)
270° — (x, y) ⇒ (y, -x)
Answer:
7cm
Step-by-step explanation:
588 / 12 = 49
= 7 * Since 7 times 7 equals 49
Answer:
The final temperature is the sum of the initial temperature and the change in temperature. The initial temperature is 102°F. The change in temperature is -3°F.
Operation:
102°F + (-3°F) = (102 - 3)°F = 99°F
Step-by-step explanation:
