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Aleksandr [31]
3 years ago
12

(a−2b)3 when a=−4 and b=−1/2

Mathematics
2 answers:
Setler [38]3 years ago
5 0

Answer:

-27

Step-by-step explanation:

Hi there!

(a-2b)^3

Plug in the given information:

(-4-2(\displaystyle -\frac{1}{2} ))^3\\\\(-4-(\displaystyle -\frac{2}{2} ))^3\\\\(-4+1)^3\\\\(-3)^3\\\\-27

I hope this helps!

Vikentia [17]3 years ago
3 0

Answer:

-9

Step-by-step explanation:

(-4-2*-1/2)3

(-4+1)3

-3*3

-9

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Pls can I have the workings too​
KengaRu [80]

Answer:

\frac{(3-2a)}{a^2}

Step-by-step explanation:

Given expression is,

\frac{3}{a^2}- \frac{2}{a}

First equalize the denominators of the fractions,

\frac{3}{a^2}-\frac{2a}{a^2}

Now combine the fraction as a single fraction,

\frac{(3-2a)}{a^2}

Since, we can not solve this fraction further, this will be simplified form of the given expression.

3 0
3 years ago
Give the number to which the Fourier series converges at a point of discontinuity of f.
quester [9]

Answer:

The Fourier series of f(x) converges to 3 at the points x= π+2kπ, where k is an integer.

Step-by-step explanation:

First, recall that the function f(x) is extended 2π periodic to the whole real line, in order to obtain a valid Fourier expansion. Remember that a Fourier series is formed by a sines and cosines, which are 2π-periodic.

So, the 2π-periodic expansion of f(x) is discontinuous at the points π+2kπ, in particular π and -π. Check the attached figure to a better understanding.

Now, the Dirichlet theorem on the convergence of a Fourier series tells us that the series converges to the function at the points of continuity, and at points of discontinuity the sum of the series is

\frac{f(x_0+)+f(x_0-)}{2}.

Here we understand the notation f(x+) and f(x-) as

f(x_0+) = \lim_{x\rightarrow x_0}f(x), x>x_0

and

f(x_0-) = \lim_{x\rightarrow x_0}f(x), x.

In this particular case

f(\pi-) = \lim_{x\rightarrow \pi}(3-2x) = 3-2\pi, x.

For the limit f(\pi+) = \lim_{x\rightarrow \pi}(3-2x), with x>\pi recall that our function is 2π-periodic, so the values of f near π, with x>π are the same when x is near -π and x>-π. Again, check the attached figure. So,

f(\pi+) = \lim_{x\rightarrow \pi}(3-2x) = 3+2\pi, x.

Thus,

\frac{f(\pi+)+f(\pi-)}{2} = \frac{3+2\pi +3-2\pi}{2} = \frac{6}{2} =3.

Note: In the attached figure we only have drawn three repetitions of the 2π-periodic extension of f, recall that the extension is <em>ad infinitum</em>. Also, the points drawn in the dotted lines are the sum of the series at the points of discontinuity.

6 0
3 years ago
Find the number of real number solutions for the equation x^2-6=0
andrew11 [14]

Answer:

Step-by-step explanation:

x^2-6=0

x^+6=0 ( add six to both sides)

x^2=6

x= the square root of 6 ( to get rid of the exponent you have to do the opposite....which is the square root)

x=2.44948974278

You may have to round if not given the exact number.

4 0
3 years ago
Read 2 more answers
The circumference of a circle can be found by multiplying Pi by the diameter. True False
Softa [21]
Here's a formula to find the circumference of a circle
c = 2 × π × r

Multiplication has commutative property, we can change the order of operands without changing the result. I move 2 to the right.
c = π × 2 × r

Remember d = 2 × r
c = π × d

The answer is true. The circumference of a circle can be found by multiplying pi by the diameter
3 0
3 years ago
4x^2+8x-12 it needs to be factored :)
Arlecino [84]

Answer:4((x+3)(x-1))

Step-by-step explanation:

Factorize the common terms

4(x^2+2x-3)

Factorize

X^2+2x-3=(x+3)(x-1)

(X+3)(x-1)

4((x+3)(x-1))

3 0
3 years ago
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