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iren2701 [21]
3 years ago
9

4 papers wide. How long in inches ?

Mathematics
2 answers:
TEA [102]3 years ago
5 0

Answer: 44 inches

Step-by-step explanation: standard printer paper is 8.5 x 11 and 8.5 x 4 = 34 & 11 x 4 = 44

topjm [15]3 years ago
3 0

Answer:

160

Step-by-step explanation:

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Hello , how to do 6(iii)?
Doss [256]

Answer:

\displaystyle \frac{dS}{dt}=\frac{3}{50r}

Step-by-step explanation:

Water is being pumped into an inflated rubber sphere at a constant rate of 0.03 cubic meters per second.

So, dV/dt = 0.03.

We want to show that dS/dt is directly proportional to 1/r.

In other words, we want to establish the relationship that dS/dt  = k(1/r), where k is some constant.

First, the volume of a sphere V is given by:

\displaystyle V=\frac{4}{3}\pi r^3

Therefore:

\displaystyle \frac{dV}{dt}=4\pi r^2\frac{dr}{dt}

Next, the surface area of a sphere S is given by:

\displaystyle S=4\pi r^2

Therefore:

\displaystyle \frac{dS}{dt}=8\pi r\frac{dr}{dt}

We can divide both sides by 2:

\displaystyle \frac{1}{2}\frac{dS}{dt}=4\pi r\frac{dr}{dt}

We can substitute this into dV/dt. Rewriting:

\displaystyle \frac{dV}{dt}=r\Big(4\pi r\frac{dr}{dt}\Big)

So:

\displaystyle \frac{dV}{dt}=\frac{1}{2}r\frac{dS}{dt}

Since dV/dt = 0.03 or 3/100:

\displaystyle \frac{3}{100}=\frac{1}{2}r\frac{dS}{dt}

Therefore:

\displaystyle \frac{dS}{dt}=\frac{3}{50r}=\frac{3}{50}\Big(\frac{1}{r}\Big)

Where k = 3/50.

And we have shown that dS/dt is directly proportional to 1/r.

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3 years ago
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