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Nutka1998 [239]
3 years ago
6

I'd really appreciate and owe it back, lovelies.

Mathematics
1 answer:
zlopas [31]3 years ago
7 0
I am 95% sure that the equation is correct

Happy easter!!!
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At any point in time, there could be bicycles, tricycles, and
Aleksandr-060686 [28]

Answer:

There may be 1 or 3 tricycles in the parking lot.

Step-by-step explanation:

Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:

13 x 4 + 1 x 3 + 1 x 2 = 57

11 x 4 + 1 x 3 + 3 x 2 = 53

10 x 4 + 3 x 3 + 2 x 2 = 53

8 x 4 + 5 x 3 + 2 x 2 = 51

10 x 2 + 1 x 3 + 4 x 4 = 39

9 x 3 + 1 x 2 + 5 x 4 = 49

Therefore, there may be 1 or 3 tricycles in the parking lot.

6 0
2 years ago
Simplify the expression.
Marizza181 [45]
\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})

\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}

\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x  \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x    \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)
6 0
3 years ago
18,000 divided by 25%
DanielleElmas [232]
Correct answer - 72000.
7 0
3 years ago
Read 2 more answers
The least common multiple of two numbers is 40. The difference of the two numbers is 2.
Ulleksa [173]
The factors of 40 are 1, 2, 4, 5, 8, 10, 20, and 40. So therefore, the numbers would be 2 and 4.
8 0
3 years ago
Help please asap aaaaaaaaaaaaaaaaaa
wel

Answer:

Step-by-step explanation:

Your exponential formula is in the form y = ab^x. In this form, the coefficient 'a' is the initial value, the y-intercept, the value when x=0. The value 'b' is the growth factor, which is 1 more than the growth rate per increment of x. This problem is asking for the growth rate to be expressed as a percentage.

__

Given p(x) = 78500(1.02^x), we can compare to the exponential function form to see that ...

  • a = 78,500
  • b = 1.02 = 1 +0.02 = 1 +2%

The value of x is zero in the year 2000, so the population that year is ...

  p(0) = a = 78,500

The increase per year is the value of 'b' with 1 subtracted:

  growth rate = 2% per year

6 0
2 years ago
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