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LekaFEV [45]
3 years ago
8

How do I give brainlist?

Mathematics
2 answers:
blsea [12.9K]3 years ago
6 0

Answer:

<em>Hi there</em>

Step-by-step explanation:

when u ask a question, other users are pleased to answer it. Whenever u have <em>TWO </em>answers u are allowed to pick which one is the <em>BEST </em>answer. There will be a yellow crown probably at the right hand corner

<em>~Your Welcome!</em>

Fofino [41]3 years ago
5 0

Answer:

If two people have answered, you chose the one you want to give brainliest, and give them a crown on their answer.

Step-by-step explanation:

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There are 9321 leaves on a tree explain why the digit 3 stay the same when
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✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

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✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The 3 remains the same when 9,321 is rounded because if you look to the right of the number in the hundreds place, you see 2. 5 and above, give it a shove (round up). 4 and below, leave it alone (round down). Since 2 is below 5, we leave it alone. So 9,321 is rounded to 9,300.

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point.
Andreyy89

Answer:

a = 9\\b = 48\\c = -1

Step-by-step explanation:

We know that:

In a deck of 52 cards there are 4 aces.

Therefore the probability of obtaining an ace is:

P (x) = 4/52

The probability of not getting an ace is:

P ('x) = 1-4 / 52

P ('x) = 48/52

In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.

For a discrete random variable V, the expected value is defined as:

E(V) = VP(V)

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.

We have the following equation for the expected value:

E(V) = \frac{4}{52}(a) + \frac{b}{52}(c)

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52

Therefore, expected value for V, the number of points obtained in the game is:

E(V) = \frac{4}{52}(9) + \frac{48}{52}(-1)

So:

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3 years ago
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