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3 years ago

To solve e4 – 3x = (4/3)x + 9 by graphing, which equations should be graphed?

Mathematics

2 answers:

ahrayia [7]3 years ago

8 0

Y = 4/3x + 9

y = e4 – 3x

There you go love

Alexus [3.1K]3 years ago

6 0

Answer:

We have to plot the system of equation as:

y=e^4 – 3 x

and y= (4/3)x + 9

step-by-step solution:

We are asked to solve a equation as:

e^4-3 x = (4/3)x + 9.

i.e. it could be represented as:

y=e^4-3 x

and y=(4/3)x + 9.

it could also be written as:

e^4-3 x-(4/3)x - 9=0

To graph the following system we have to graph the equation as:

y=e^4 – 3 x

and y= (4/3)x + 9

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Answer:

Step-by-step explanation:

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3 years ago

The smallest square number which can be divisible by 11 and 5

Elena L [17]

Answer:

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Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

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therefore the number is 55x, where x is a positive integer.

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therefore the square root of 55x must be an integer.

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3 years ago

Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m

Molodets [167]

Answer:

$\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

Step-by-step explanation:

We want to find $\lim_{x \to 2^-} \frac{|x-2|}{x-2}$ .

By definition:

$|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:$

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}$ .

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1)$ .

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3 years ago

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liberstina [14]

Step-by-step explanation:

7=4y-13

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3 years ago

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lora16 [44]

Answer:

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Step-by-step explanation:

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