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3 years ago

Which of the following is a situation in which an equation cannot be solved

Mathematics

2 answers:

Dimas [21]3 years ago

4 0

The answer for this problem is B

Klio2033 [76]3 years ago

3 0

Answer:

B One term of the polynomial has a degree of 3

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A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

NEED ANSWER QUICK PLSSSS

Gelneren [198K]

Answer:

CCC

Step-by-step explanation:

7 0

2 years ago

Help 2,4+0,8=.......-0,06=........+1,21=.......+1,78=....-5,14=.

horrorfan [7]

Lets write this out:-

2.4 + 0.8 =______ - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___

So to solve d blanks we will do d following:-

2.4 + 0.8 = 3.2

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___

Now lets solve again:-

3.2 - 0.06 = 3.14

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21=_____+1.78=_____- 5.14=___

Now lets solve again:-

3.14 + 1.21= 4.25

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78=_____- 5.14=___

Now lets solve again:-

4.25 +1.78= 6.03

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14=___

Now lets solve again:-

6.03 - 5.14 = 0.89

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89

So, 2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89

Hope I helped ya!! xD

3 0

3 years ago

Tell whether this statement is sometimes, always, or never true. Identify the answer with a sketch. If B is a point between A an

Ksivusya [100]

The statement is always true

7 0

2 years ago

In a board game, Rose gets x + 4 points when she lands on a green space, 7x – 1 points for landing on a blue space, and -4x poin

ra1l [238]

Answer:

5x-3

Step-by-step explanation:

x+4+7x-1-4x

5x-3

3 0

2 years ago

Read 2 more answers