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Anastasy [175]
3 years ago
11

Square root 2 is between 1.4 and 1.5

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0
1.4 < \sqrt2 < 1.5-TRUE,\ because\\\\1.4=\sqrt{1.4^2}=\sqrt{1.96} < \sqrt2\\\\1.5=\sqrt{1.5^2}=\sqrt{2.25} > \sqrt2
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Richards Middle School is collecting canned foods. The school has a goal of collecting at least 2000 cans. We have 872 cans so f
a_sh-v [17]

Answer:

141 cans per day

Step-by-step explanation:

2000 goal cans - 872 collected cans = 1,128 still needed

1,128/8 days = 141 cans per day

5 0
2 years ago
Read 2 more answers
In a flower garden, there are 4 tulips for every 9 daisies. If there are 24 tulips, how many daisies are there? Please help i wi
miss Akunina [59]

54 daisies is the answer


Hope you have a good day!



4 0
3 years ago
Amy has to write a paper for school that has more than 2,878 words. She has already written 1,037 words and writes at a rate
densk [106]

Answer:

C

Step-by-step explanation:

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7 0
3 years ago
The gross domestic product​ (in billions of​ dollars) can be approximated by ​p(t)equals564 plus t left parenthesis 36 t supersc
nirvana33 [79]

We have been given gross domestic product​ (in billions of​ dollars) can be approximated by P(t)=564+t(36t^{0.6}-101).

(a) In this part, we need to compute the derivative of this function:

P'(t)=\frac{d}{dt}(564+t(36t^{0.6}-103))\\P'(t)=\frac{d}{dt}(564)+\frac{d}{dt}(t(36t^{0.6}-103))\\P'(t)=0+57.6t^{0.6}-103\\

P'(t)=57.6t^{0.6}-103

(b) In this part, we need to find the value of P'(45). So, we will substitute t=45

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(c) P'(45)=462.39 represents that 45 years after 1960, that is, in 2005, the GCP was changing at a rate of 462.39 billion dollars per year.



4 0
3 years ago
What should be added to 6.125 to get 10
WITCHER [35]
3.875 Should be adding to 6.125 to get 10, however if you want an easier way of checking this. Do 3.875 + 6.125 and you'll get exactly 10. Click thanks <3
4 0
2 years ago
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