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Anastasy [175]
3 years ago
11

Square root 2 is between 1.4 and 1.5

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0
1.4 < \sqrt2 < 1.5-TRUE,\ because\\\\1.4=\sqrt{1.4^2}=\sqrt{1.96} < \sqrt2\\\\1.5=\sqrt{1.5^2}=\sqrt{2.25} > \sqrt2
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Solve the inequality 2x + 8 &lt; 5x − 4.
Alika [10]

Answer:

x>4

Step-by-step explanation:

2x+8<5x-4

4+8<5x-2x

12<3x

4<x

x>4

6 0
4 years ago
Please help me ASAP!! Will give Brainliest to correct answer!!!
tensa zangetsu [6.8K]

Answer:

"SAS" is when we know two sides and the angle between them. Then use the three angles add to 180° to find the last angle.

Step-by-step explanation:

The angle must be between the two sides

8 0
3 years ago
Read 2 more answers
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
Find the length of the third side. If necessary, round to the nearest tenth.
Mama L [17]

Answer:

24

Step-by-step explanation:

Use the pythagorean theorem.

7 0
3 years ago
What is the equation of a line passing through (-6, 5) and having a slope of 1/3 ? A. B. C. D. y = 3x + 7
stepan [7]

Answer:

y = 1/3 x + 7

Step-by-step explanation:

Given; the line is passing through, (-6,5) and the slope is 1/3

We can get its equation;

We would take, a point (x,y) and the given point (-6,5)

Therefore; Since slope = Δy/Δx

Then;

(5-y)/ (-6-x) = 1/3

3(5-y) = -6 -x

15 - 3y = -6 - x

we get;

3y = 6 + x + 15

3y = x + 21

Therefore;

<u>y = 1/3 x + 7</u>

3 0
4 years ago
Read 2 more answers
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