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Leni [432]
3 years ago
7

What are supersonic speeds

Mathematics
2 answers:
Darya [45]3 years ago
6 0

Answer:

speeds above 343 m/s

Step-by-step explanation:

the faster you go the faster the supersonic

siniylev [52]3 years ago
4 0
Speeds above 343 excell
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5x+1=20 what do x equal
frez [133]
X = 3.8

5x+1=20
Subtract 1 on both sides to get:
5x=19
Divide by 5 on both sides to get:
x=19/5

You can leave it as a fraction as 19/5, or convert to a decimal as 3.8.
4 0
3 years ago
Read 2 more answers
(x+3)(3x² - 5x - 10) multiply polynomial
brilliants [131]

Answer:

  • \boxed{\sf{3x^3+4x^2-25x-30}}

Step-by-step explanation:

\underline{\text{SOLUTION:}}

To isolate the term of x from one side of the equation, you must multiply by a polynomial.

\underline{\text{GIVEN:}}

:\Longrightarrow: \sf{(x+3)(3x^2 - 5x - 10)}

<u>You have to solve with parentheses first.</u>

:\Longrightarrow \sf{x\cdot \:3x^2+x\left(-5x\right)+x\left(-10\right)+3\cdot \:3x^2+3\left(-5x\right)+3\left(-10\right)}

<u>Solve.</u>

\sf{x*3x=3x^3}

x(-5x)=-5x²

\sf{x(-10)=-10x}

3*3x²=9x²

3(-5x)=-15x

3(-10)=-30

<u>Then, rewrite the problem down.</u>

\sf{3x^3-5x^2-10x+9x^2-15x-30}

<u>Combine like terms.</u>

\Longrightarrow: \sf{3x^3-5x^2+9x^2-10x-15x-30}

<u>Add/subtract the numbers from left to right.</u>

-5x²+9x²=4x²

\Longrightarrow: \sf{3x^3+4x^2-10x-15x-30}

<u>Solve.</u>

\sf{-10x-15x=-25x}

<u>Then rewrite the problem.</u>

\Longrightarrow: \boxed{\sf{3x^3+4x^2-25x-30}}

  • <u>Therefore, the correct answer is 3x³+4x²-25x-30.</u>

I hope this helps! Let me know if you have any questions.

6 0
2 years ago
Read 2 more answers
Help this is my exit ticket HURRY LOTS OF POINTS
lisov135 [29]

Answer:

The answer for this question ( ur exit ticket ) is C .

6 0
2 years ago
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A high school guidance counselor determined the following information regarding students and their likelihood of playing a sport
iogann1982 [59]

Conditional Probability

Given two events A and B (not excluding), the probability that A occurs given that B has occurred is called a <em>conditional probability</em> and is calculated as:

P(A|B)=\frac{P(A\cap B)}{P(B)}

Where P(A∩B) is the probability that A and B occur simultaneously and P(B) is the probability that B occurs.

Now with the given data, we must find the values of the required probabilities.

30% of the students play a sport (S), this means that:

70% of the students don't play a sport (NS).

65% of the students have a job.

Note that there could be students who both play sports and have a job.

Of the 30% of the students who play a sport, 50% have a job. This means that:

15% of the students play a sport and don't have a job

15% of the students play a sport AND have a job

65% - 15% = 50% of the students have a job and don't play a sport

That last number is the numerator of the equation given above:

P(A∩B) = 0.5

The event B corresponds to students that don't play a sport (NS), thus:

P(B) = 0.7

Thus we have:

P(A|B)=\frac{0.5}{0.7}=\frac{5}{7}

The required probability is 5/7 or 0.7143

4 0
1 year ago
Can you help and do it step by step
MrRa [10]

Answer:

$4800

Step-by-step explanation:

SI=PRT DIVIDED BY 100..

So it is going to be 400×2×6 divided by 100 which will be 4800

6 0
3 years ago
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