Find the value of x. Round the length to the nearest tenth.

Each of 8 ladies randomly chooses a woolen overcoat from 14 different styles. What is the probability that at least 2 ladies cho

Sophie [7]

Answer: 0.894

Step-by-step explanation:

5 0

3 years ago

Which equation represents the graph below?

Art [367]

I thinks it’s B because up it’s y and down its -y and right is X and left is -X

6 0

3 years ago

Mrs. Dodson has a jar full of pennies and quarters. There are 120 coins in the jar worth a

Anton [14]

Answer: 10.

Step-by-step explanation:

DIVISION. 120/12.

That is hard! Here's a trick.

12x9= 99=9=108. Or 12x6=66+6=72.

We will stick with 12x9, that equals 108.

We should add another 12 until we get to 120.

108+12=120. That is 10 times. The trick was...

dividing by 12 is hard, so lets say 12x4. I can put 4 and 4 together.

44 then and another 4. That is 48. So 12x4=48.

5 0

3 years ago

there are 5 pics with multiple questions inside them if you do finish this one the will be more on my questions list on my profi

BigorU [14]

Answer:

15) choice 1

16) choice 4, 72 degrees

17) choice 3) translation

18) choice 3, never

19) choice 3) 2

20) choice 3

21) acute triangle, at least one angle less than 90 degrees

Step-by-step explanation:

3 0

3 years ago

The drag Prevnar is a vaccine meant to prevent meningitis. It is typically administered to infants between 12 and 15 months of a

Fed [463]

Answer:

The pvalue of the test is 0.0058 < 0.01, which means that there is significant evidence to conclude the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135.

Step-by-step explanation:

Test if the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135

This means that the null hypothesis is:

$H_{0}: p = 0.135$

And the alternate hypothesis is:

$H_{a}: p \neq 0.135$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.135 is tested at the null hypothesis:

This means that $\mu = 0.135, \sigma = \sqrt{0.135*0.865}$

Of the 710 infants,121 experienced a loss of appetite.

This means that $n = 710, X = \frac{121}{710} = 0.1704$

Value of the test-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.1704 - 0.135}{\frac{\sqrt{0.135*0.865}}{\sqrt{710}}}$

$z = 2.76$

Pvalue of the test and decision:

The pvalue of the test is the pobability that the population proportion differs from the tested proportion by at least 0.1704 - 0.135 = 0.0354, which is P(|z| > 2.76). This probability is 2 multiplied by the pvalue of z = -2.76.

Looking at the z-table, z = -2.76 has a pvalue of 0.0029

2*0.0029 = 0.0058

The pvalue of the test is 0.0058 < 0.01, which means that there is significant evidence to conclude the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135.

7 0

3 years ago