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san4es73 [151]
2 years ago
8

Help please asap algebra 2

Mathematics
1 answer:
timurjin [86]2 years ago
4 0
X = approximately 633

Steps:
lnx + ln3x = 14

ln3x^2 = 14 : Use the log property of addition which is to multiply same log                           together so you multiply x and 3x because they have log in                                common

  (ln3x^2) =  (14)  : take base of e on both sides to get rid of the log
e                e

3x^2 = e^14  : e cancels out log on the left side and the right side is e^14 

x^2 = e^14 / 3 : divide both sides by 3

√x^2 = <span>√(e^14 / 3) : take square root on both sides to get rid of the square 2                                  on x
</span>
x = √(e^14) / <span>√3 : square root cancels out square 2 leaving x by itself

x = e^7 / </span>√3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7<span>

x = </span>633.141449221 : solve 
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A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

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Answer: i think it is about 3.6%


Step-by-step explanation:


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