Answer:
Step-by-step explanation:
Using brackets will really help.
y = (x^2 + 4x + ... ) - 5 You are trying to complete the square. The square in this case is a trinomial that is squared.
To do that, you take 1/2 the linear term (4x)/2, drop the x (4/2), and square the result (4/2)^2. The number is 2^2 which is 4.
So far what you have is
y = (x^2 + 4x + 4) - 5
Now you just can't add 4 without adjusting it somehow. If you do, the whole question will change it's value. Because you added 4 inside the brackets, you must subtract 4 outside the brackets.
What that means is 4 inside - 4 outside. So it looks like this
y = (x^2 + 4x + 4) - 5 - 4
Now you continue on
y = (x + 2)^2 - 9 The 4 combines with the 5 to make nine.
Answer:
y = 20.922
Step-by-step explanation:
Simply plug in <em>x</em> and evaluate:
y = 15 + 3ln(7.2)
Only way to calculate ln is to plug into a calc:
We should get 20.9222 as our answer.
Answer:
Part A
The bearing of the point 'R' from 'S' is 225°
Part B
The bearing from R to Q is approximately 293.2°
Step-by-step explanation:
The location of the point 'Q' = 35 km due East of P
The location of the point 'S' = 15 km due West of P
The location of the 'R' = 15 km due south of 'P'
Part A
To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that 
= 
, the right triangle ΔRPS is an isosceles right triangle
∴ ∠PRS = ∠PSR = 45°
The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°
Part B
∠PRQ = arctan(35/15) ≈ 66.8°
Therefore the bearing from R to Q = 270 + 90 - 66.8 ≈ 293.2°
Answer:
-25
Step-by-step explanation:
sorry for the mistake
