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pochemuha
3 years ago
5

Find the value of x in each case

Mathematics
1 answer:
yanalaym [24]3 years ago
8 0

Answer:

x = 69

Step-by-step explanation:

m<M = x

From the triangle we know that

m<M + m<MNQ + m<MQN = 180

From the parallel lines we know that

m<MNQ = m<UQN = x

x + x + 42 = 180

2x + 42 = 180

2x = 138

x = 69

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
2 years ago
Can you figure thus out?
babymother [125]

Answer:

315

Step-by-step explanation:

The number is divisible by 3,5,7 and 9. Since 3 is a factor of 9, this number is divisible by 5,7, and 9.

5x7x9= 315.

3 0
1 year ago
Evaluate 1/3 divided by 1/2
svp [43]

Answer:

2/3

Step-by-step explanation:

1/3 x 2/1 = 2/3

3 0
3 years ago
Read 2 more answers
What is the slope of the line that has the equation 4x + 2y = 12?
WARRIOR [948]

Answer:

The slope is -2

Step-by-step explanation:

convert to slope intercept form. the number or fraction by the x when in slope intercept form is the slope.

6 0
3 years ago
Read 2 more answers
Find a direct relationship between x and y.<br> x = 3t and y = 2t + 7
ikadub [295]

Answer:

y = \frac{2}{3} x + 7

Step-by-step explanation:

Given

x = 3t ( divide both sides by 3 )

\frac{1}{3} x = t

Substitute this value into y = 2t + 7

y = 2 × \frac{1}{3} x + 7 = \frac{2}{3} x + 7

6 0
2 years ago
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