Question

Find the first four terms of the sequence given by the following. an= 4(2)^n-1 n=1, 2, 3...

Answer 1

Answer + Step-by-step explanation:

an= 4(2)ⁿ⁻¹

First term (n = 1) :

a1= 4(2)¹⁻¹ = 4(2)⁰ = 4×(1) = 4

Second term (n = 2) :

a2= 4(2)²⁻¹ = 4(2)¹ = 4×(2) = 8

Third term (n = 3) :

a3= 4(2)³⁻¹ = 4(2)² = 4×(4) = 16

Fourth term (n = 4) :

a4= 4(2)⁴⁻¹ = 4(2)³ = 4×(8) = 32