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Nesterboy [21]
2 years ago
11

Find the first four terms of the sequence given by the following. an= 4(2)^n-1 n=1, 2, 3...

Mathematics
1 answer:
mr_godi [17]2 years ago
4 0

Answer + Step-by-step explanation:

an= 4(2)ⁿ⁻¹

<u>First term (n = 1)</u> :

a1= 4(2)¹⁻¹ = 4(2)⁰ = 4×(1) = 4

<u>Second term (n = 2)</u> :

a2= 4(2)²⁻¹ = 4(2)¹ = 4×(2) = 8

<u>Third term (n = 3)</u> :

a3= 4(2)³⁻¹ = 4(2)² = 4×(4) = 16

<u>Fourth term (n = 4)</u> :

a4= 4(2)⁴⁻¹ = 4(2)³ = 4×(8) = 32

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Answer:

1,128

Step-by-step explanation:

94 x 12 = 1,128

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1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

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Answer:

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