Question

What is the tru solution to the logarithmic equation below? Log4[log4(2x)]=1

Answer 1

$\log_4(\log_42x)=1$

Take both sides as powers of 4:

$4^{\log_4(\log_42x)}=4^1\implies\log_42x=4$

Do it again:

$4^{\log_42x}=4^4\implies2x=(2^2)^4=2^8\implies x=2^7=128$