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Colt1911 [192]
3 years ago
10

What is the tru solution to the logarithmic equation below? Log4[log4(2x)]=1

Mathematics
1 answer:
zaharov [31]3 years ago
3 0

\log_4(\log_42x)=1

Take both sides as powers of 4:

4^{\log_4(\log_42x)}=4^1\implies\log_42x=4

Do it again:

4^{\log_42x}=4^4\implies2x=(2^2)^4=2^8\implies x=2^7=128

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