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3 years ago

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A car leaving a stop sign accelerates...what is the average speed of the car, in feet per second, equation d=1.1t^2 average spee

d
between t=2 and t=5?

1 answer:

spayn [35]3 years ago

8 0

Answer:

10.27 feet/sec.

Step-by-step explanation:

The distance traveled by the car, d in feet, is given by the function $d = 1.1t^{2}$ .......... (1), where t is the time in seconds.

So, at t= 2 sec, from equation (1) we get d = 1.1 × 4 = 4.4 feet.

Again, at t = 5 sec, we get d = 1.1 × 32 = 35.2 feet.

Now, average speed of the car from t = 2 sec. to t = 5 sec. will be give by

$\frac{\textrm {Total distance traveled}}{\textrm {Total time spent}}$

= $\frac{35.2 - 4.4}{5 - 2} = 10.27$ feet/sec. (Answer)

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Alchen [17]

Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
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Input the information from the diagram into the formula:
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Expand each term:
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Add -169 to both sides:
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However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is:
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I hope this helped!
-Benjamin

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