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2 years ago

In TUV the measure of V=90 TU=88 and UV=43 feet. Find the measure of T to the nearest tenth of a degree

Mathematics

2 answers:

Nimfa-mama [501]2 years ago

6 0

Answer:

29.3

Step-by-step explanation:

T=29.251\approx 29.3^{\circ}

T=29.251≈29.3

ps. i just did it

LekaFEV [45]2 years ago

5 0

Answer:

m∠T = 27.9°

Step-by-step explanation:

Use the law of cosines

$UV^{2} = TU^{2} + UV^{2} - 2(TU)(UV)cos T\\43^{2} = 88^{2} + 90^{2} - 2(88)(90) cos T\\1849 = 7744 + 8100 - 15840 cos T\\1849 = 15844 - 15840 cos T\\-13995 = - 15840 cos T\\cos T = \frac{-13995}{-15840} = .883522...\\T = arccos .883522... = 27.9$

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In TUV the measure of V=90 TU=88 and UV=43 feet. Find the measure of T to the nearest tenth of a degree​

In TUV the measure of V=90 TU=88 and UV=43 feet. Find the measure of T to the nearest tenth of a degree