Question

In TUV the measure of V=90 TU=88 and UV=43 feet. Find the measure of T to the nearest tenth of a degree​

Answer 1

Answer:

29.3

Step-by-step explanation:

T=29.251\approx 29.3^{\circ}

T=29.251≈29.3

ps. i just did it

Answer 2

Answer:

m∠T = 27.9°

Step-by-step explanation:

Use the law of cosines

$UV^{2} = TU^{2} + UV^{2} - 2(TU)(UV)cos T\\43^{2} = 88^{2} + 90^{2} - 2(88)(90) cos T\\1849 = 7744 + 8100 - 15840 cos T\\1849 = 15844 - 15840 cos T\\-13995 = - 15840 cos T\\cos T = \frac{-13995}{-15840} = .883522...\\T = arccos .883522... = 27.9$