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Sliva [168]
3 years ago
5

In TUV the measure of V=90 TU=88 and UV=43 feet. Find the measure of T to the nearest tenth of a degree​

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
6 0

Answer:

29.3

Step-by-step explanation:

T=29.251\approx 29.3^{\circ}

T=29.251≈29.3

ps. i just did it

LekaFEV [45]3 years ago
5 0

Answer:

m∠T = 27.9°

Step-by-step explanation:

Use the law of cosines

UV^{2}  =  TU^{2}  +  UV^{2}  - 2(TU)(UV)cos T\\43^{2}  =  88^{2}  +  90^{2}  - 2(88)(90) cos T\\1849  =  7744  +  8100  -  15840 cos T\\1849 = 15844 - 15840 cos T\\-13995  =  - 15840 cos T\\cos T =  \frac{-13995}{-15840}  = .883522...\\T =  arccos .883522... = 27.9

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An object falls 16 t 2 16t2 feet in t t seconds. You drop a rock from a bridge that is 75 feet above the water. Will the rock hi
GuDViN [60]

Answer:

No it is still 11 feet from the water at 2 seconds

2.1651 seconds  is when it will hit the water

Step-by-step explanation:

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This is the formula  for the distance

The -16t^2 is due to gravity and the 75 is the height above the bridge

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Divide by -16

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