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Sliva [168]
2 years ago
5

In TUV the measure of V=90 TU=88 and UV=43 feet. Find the measure of T to the nearest tenth of a degree​

Mathematics
2 answers:
Nimfa-mama [501]2 years ago
6 0

Answer:

29.3

Step-by-step explanation:

T=29.251\approx 29.3^{\circ}

T=29.251≈29.3

ps. i just did it

LekaFEV [45]2 years ago
5 0

Answer:

m∠T = 27.9°

Step-by-step explanation:

Use the law of cosines

UV^{2}  =  TU^{2}  +  UV^{2}  - 2(TU)(UV)cos T\\43^{2}  =  88^{2}  +  90^{2}  - 2(88)(90) cos T\\1849  =  7744  +  8100  -  15840 cos T\\1849 = 15844 - 15840 cos T\\-13995  =  - 15840 cos T\\cos T =  \frac{-13995}{-15840}  = .883522...\\T =  arccos .883522... = 27.9

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What’s the equation for A slope =2 through the point (2,1)?
Fiesta28 [93]

Answer:

y = 2x - 3

Step-by-step explanation:

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4 0
3 years ago
The graph of F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x). If F(x) = x^2, which of
katrin [286]

The transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The options are missing.

The options are:

A. G(x) = 4x²

B. G(x) = -(1/4)x²

C. G(x) = -4x²

D. G(x) = (1/4)x²

We have an equation of a function F(x)  

F(x) = x²

The transformation F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x)

To stretch vertically if the function is multiplied by a constant value

f(x) = ax²

To flip over the x-axis if multiply by negative value.

g(x) = -ax²

From the options

G(x) = -4x²

Thus, the transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.

Learn more about the function here:

brainly.com/question/5245372

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6 0
1 year ago
A child's sandbox is 5 feet wide, 4 feet long, and 3 feet deep. Grace fills the sandbox so that the sand is 2 ½ feet deep. What
8_murik_8 [283]

Answer:

the volume of sand is 50 ft^{3}

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, rectangular prism.

Given data

Length  l= 4 ft Width w= 5ft\\Height h = 3ft

if the sandbox is filled with sand of 2\frac{1}{2 } ft deep the volume of the sand in the box will be calculated based on the the depth of the sand

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the expression for the volume of a rectangular prism is

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substituting our data into the expression we have

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