we are given

now, we can compare it with

we can find b
we get

now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8

b=1.6

b=1.4

b=1.2

now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
Answer: 
<u>Step-by-step explanation:</u>
Average rate of change is the slope (m) between the two coordinates (-1, -1) and (1, -2).



Answer:
B
Step-by-step explanation:
110 / 22 = 5 inches per picket
equation is y = 5x
Answer:
1; after 2 months
2; $130
Step-by-step explanation:
In this question, we are trying to compare the fees to be paid in two different gyms, to determine when the amount paid would be equal and also what this amount would be.
Now since we do not know the exact number of months, we can represent this unknown by x
so mathematically, at the end of m months, at the first gym , Casey would have paid a total of 50 + 40m
For the second gym, at the end of the second month, casey would have paid a total of 65m only
now we need to know when these fees would be the same. we simply equate what we have on both ends
mathematically, that is 50 + 40m = 65m
65m-40m = 50
25m = 50
m = 50/25
m = 2 months
The fees to be paid is
50 + 40(2) = 65(2) = $130