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IRINA_888 [86]
3 years ago
10

Is 15,36,39 a right triangle

Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

Yes, is a right triangle

Step-by-step explanation:

To know if you can build a right triangle with those sides we have to make the following equality

h² = l1² + l2²

The hypotenuse is always the longest side so it should be 39

we check the equality of the equation

39² = 15² + 36²

1521 = 225 + 1296

1521 = 1521

Equality was fulfilled so it is a right triangle

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Kiara spent $36 and had $12 left.<br><br> what percent money did she spend
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Find the product of the roots of the equation<br> xl-5x - 36 = 0
Marat540 [252]

Answer:

Step-by-step explanation:

Hello, I assume that you mean

x^2-5x-36

The product is -36.

x_1 \text{ and } x_2 \text{ are the two roots, we can write}\\\\(x-x_1)(x-x_2)=x^2-(x_1+x_2)x+x_1\cdot x_2

So in this example, it means that the sum is 5 and the product is -36.

Thank you

5 0
3 years ago
Solve for x: 8 (3x + 10) = 28x - 14 - 4x ​
Ierofanga [76]

Answer:

8(3x + 10) = 28x - 14 - 4x \\ 8 \times 3x + 8 \times 10 = 28x - 14 - 4x \\ 24x + 80 = 24x - 14 \\ 0x = 94 \\ x =  > has \: no \: solution

6 0
2 years ago
Find the surface area of the following figure.
fgiga [73]

Answer:

\boxed{\textsf{\pink{ Hence the TSA of the cuboid is $\sf 32x^2$}}}.

Step-by-step explanation:

A 3D figure is given to us and we need to find the Total Surface area of the 3D figure . So ,

From the cuboid we can see that there are 5 squares in one row on the front face . And there are two rows. So the number of squares on the front face will be 5*2 = 10 .

We know the area of square as ,

\qquad\boxed{\sf Area_{(square)}= side^2}

Hence the area of 10 squares will be 10x² , where x is the side length of each square. Similarly there are 10 squares at the back . Hence their area will be 10x² .

Also there are in total 12 squares sideways 6 on each sides . So their surface area will be 12x² . Hence the total surface area in terms of side of square will be ,

\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies\boxed{\sf TSA_{(cuboid)}= 32x^2}

Now let's find out the TSA in terms of side . So here the lenght of the cuboid is equal to the sum of one of the sides of 5 squares .

\sf\implies 5x = l \\\\\sf\implies x = \dfrac{l}{5} \\\\\qquad\qquad\underline\red{ \sf Similarly \ breadth }\\\\\sf\implies b = 3x  \\\\\sf\implies x = \dfrac{ b}{3}

\rule{200}2

Hence the TSA of cuboid in terms of lenght and breadth is :-

\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies TSA_{(cuboid)}= 20\bigg(\dfrac{l}{5}\bigg)^2+12\bigg(\dfrac{b}{3}\bigg) \\\\\sf\implies TSA_{(cuboid)}= 20\times\dfrac{l^2}{25}+12\times \dfrac{b^2}{9}\\\\\sf\implies \boxed{\red{\sf TSA_{(cuboid)}= \dfrac{4}{5}l^2 +\dfrac{4}{3}b^2 }}

6 0
2 years ago
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