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sasho [114]
4 years ago
12

The average price of a gallon of milk is $3.31. If the price increases .88% each year , how much will a gallon of milk cost in 2

0 years?
Mathematics
1 answer:
musickatia [10]4 years ago
5 0

Answer:

$3.94

Step-by-step explanation:

You will need to use the compound interest formula for this.

P(1+\frac{r}{n} )^{nt}

P = initial balance

r = interest rate

n = number of times compounded annually

t = time

Your equation will look like this:

3.31(1+\frac{.0088}{1} )^{20} = 3.94

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1/(x-1)x+1/x(x+1)+...+1/(x+9)(x+10)=11/12
nata0808 [166]

Notice that

\dfrac1{(x-1)x} = \dfrac1{x-1} - \dfrac1x \\\\ \dfrac1{x(x+1)} = \dfrac1x - \dfrac1{x+1} \\\\ \vdots \\\\ \dfrac1{(x+9)(x+10)} = \dfrac1{x+9} - \dfrac1{x+10}

That is, the <em>n</em>-th term (where <em>n</em> = -1, 0, 1, …, 9) in the sum on the left side has a partial fraction decomposition of

\dfrac{1}{(x+n)(x+n+1)} = \dfrac1{x+n} - \dfrac1{x+n+1}

and in the sum, some adjacent terms will cancel and leave you with

\dfrac1{(x-1)x} + \dfrac1{x(x+1)} + \cdots + \dfrac1{(x+9)(x+10)} = \dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}

Now solve for <em>x</em>, bearing in mind that we cannot have <em>x</em> = 0, -1, -2, …, -10 :

\dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}

Combine the fractions on the left side:

\dfrac{(x+10)-(x-1)}{(x-1)(x+10)} = \dfrac{11}{(x-1)(x+10)} = \dfrac{11}{12}

Then we must have

(x-1)(x+10) = x^2 + 9x - 10 = 12 \implies x^2+9x-22 = (x+11)(x-2) = 0

so that either <em>x</em> = 2 or <em>x</em> = -11.

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3 years ago
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