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Anton [14]
3 years ago
13

What is the slope of y= -3/5x-2

Mathematics
2 answers:
ss7ja [257]3 years ago
8 0
Valer is right k bye now ! C:
Anna007 [38]3 years ago
7 0

Answer: -3/5 would be the slope

Step-by-step explanation:

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Help me please thank you
Usimov [2.4K]

Answer:

x = 7

Step-by-step explanation:

5x + 9 = 6x + 2

5x - 6x = 2 - 9

-x = -7

x = 7

probe:

5*7 + 9 = 6*7 + 2

35 + 9 = 42 + 2 = 44

7 0
3 years ago
Read 2 more answers
Find the median, mean, and range.
RSB [31]

Hey there!

The median is 8.5

The mean is 7

The range is 11

Hope this helps!

God bless ❤️

xXxGolferGirlxXx

5 0
4 years ago
A test is worth 100 points. The test is made up of 40 items. Each item is worth either 2 points or 3 points. Which matrix equati
lidiya [134]

Answer:

Total number of points in the test = 100

Total number of items in the test = 40

Let number of items of 2 points be x and number of items of 3 points be y.

Now, using the given information the situation can be represented by using the following equations :

⇒ x + y = 40 .........(1)

⇒ 2x + 3y = 100 .........(2)

The matrix equation is :

\begin{bmatrix}1 & 1\\ 2& 3\end{bmatrix}\cdot \begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}40\\ 100\end{bmatrix}

By solving the equation (1) and equation (2), we get :

Solution : x = 20 and y = 20

4 0
4 years ago
Read 2 more answers
Which property is illustrated by the equation 2+8=8+2?
vodomira [7]

Answer:

communicative, you can remember this by saying  (the rule for the communicative property, is as easy as can be, just remember a+b is the same as b+a )

6 0
3 years ago
Read 2 more answers
The accompanying data contains the depth​ (in kilometers) and​ magnitude, measured using the Richter​ Scale, of all earthquakes
Sunny_sXe [5.5K]

Answer:

Depth:

μ =20.2025 km

M = 15.625 km

Range = 47.15 km

σ ≈ 15.92 km

Q₁ = 5.7375 km

Q₃ =  34.6675 km

Magnitude:

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

Step-by-step explanation:

The given data are;

Depth {}                                 Magnitude

0.76 {}                                    0.84

4.93 {}                                    0.47

8.16 {}                                     0.35

33.58 {}                                  1.32

21.2 {}                                     1.61

35.03 {}                                  4.57

10.05 {}                                   5.52

47.91 {}                                    1.99

For the Depth, we have;

The mean, μ = (0.76+4.93+8.16+33.58+21.2+35.03+10.05+47.91)/8 =20.2025 km

The median, M = The (n + 1)/2th term after arranging the term in increasing order as follows;

0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 , the median is therefore;

(8 + 1)/2th term or the 4.5th term which is 10.05 + (21.2 - 10.05)/2 = 15.625 km

The Range = The highest - The lowest value = 47.91 - 0.76 = 47.15 km

The Standard deviation of, σ, is given as follows;

\sigma =\sqrt{\dfrac{\sum \left (x_i-\mu  \right )^{2} }{N}}

Where;

x_i = The individual data point = (0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 )

N = The total number of data point = 8

Substituting, (using Microsoft Excel) we get;

\sigma =\sqrt{\dfrac{\sum \left (x_i-20.2025  \right )^{2} }{8}} \approx 15.92 \ km

Q₁ = The first quartile = The (n + 1)/4th =  term arranged in increasing order

Q₁ = The (8 + 1)/4th term = The 2.25th term = 4.93 + (8.16 - 4.93)×0.25) = 5.7375 km

Q₃ = The first quartile = The 3×(n + 1)/4th =  term arranged in increasing order

Q₃ = The 3×(8 + 1)/4th term = The 6.75th term = 33.58 + 3×(35.03 - 33.58)×0.25) = 34.6675 km

For the magnitude, we have, using the same formulas and procedures as above;

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

4 0
4 years ago
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