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elena-s [515]
2 years ago
9

In Exercise find the derivative of the functions. f(x) = 3/7x^2

Mathematics
1 answer:
Sedbober [7]2 years ago
4 0

Answer:

\dfrac{d(f(x))}{dx} = \dfrac{-6}{7}x^{-3}

Step-by-step explanation:

We are given the following in the question:

f(x) = \dfrac{3}{7x^2}

We have to find derivative of the given function

Formula:

\dfrac{d(x^n)}{dx} = nx^{n-1}

Derivation the given function we get:

\dfrac{d(f(x))}{dx} = \dfrac{d}{dx}\bigg(\dfrac{3}{7x^2}\bigg)\\\\=\dfrac{d}{dx}\bigg(\dfrac{3x^{-2}}{7}\bigg)\\\\=\dfrac{3}{7}(-2)(x^{-2-1})\\\\=\dfrac{-6}{7}x^{-3}

\dfrac{d(f(x))}{dx} = \dfrac{-6}{7}x^{-3}

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Answer:

     <u>First figure:</u>            954cm^3

     <u>Second figure:</u>      1,508yd^3

     <u>Third figure:</u>

  •          Height= q
  •           Side length = r

     <u>Fourth figure: </u>        726cm^3

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

            \text{Volume of a cylinder}=\pi \times radius^2\times length

<u>2. Data:</u>

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<u>3. Substitute in the formula and compute:</u>

          Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3

<u>B. Second figure</u>

<u>1. Formula: </u>

       \text{Volume of a leaned cylinder}=\pi \times radius^2\times height

<u>2. Data:</u>

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<u>3. Substitute and compute:</u>

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<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u>  </u><u>q  </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u>  r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

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The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

          Volume=(1/3)B\times H

<u>2. Data: </u>

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<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

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