Answer:
6 ways - ab,ac, ba,bc and ca,cb
Step-by-step explanation:
We are given 3 letters a,b,c.
We can choose the first letter in 1 out of 3 ways.
Once the first letter has been chosen without replacement, we have two letters remaining. Another letter can be chosen from the 2 remaining letters in 2 ways. So the total number of ways of choosing the two letters is 3*2 = 6.
Listing out the possible set of choices:
Options include: ab,ac, ba,bc and ca, cb
Answer: 46 years
Step-by-step explanation:
Let the father's age be x and the son's age be y, then 3 years ago:
Father = x - 3
son = y - 3
Then , from the first statement :
x - 3 = 3 ( y - 3 )
x - 3 = 3y - 9
x = 3y - 9 + 3
x = 3y - 6 .......................................... equation 1
In five years time
father = x + 5
son = y + 5
Then , from the second statement
x + 5 = 2 ( y + 5 )
x + 5 = 2y + 10
x = 2y + 10 - 5
x = 2y + 5 ........................ equation 2
Equating equation 1 and 2 , we have
3y -6 = 2y + 5
add 6 to both sides
3y = 2y + 5 + 6
subtract 2y from both sides
3y - 2y = 11
y = 11
substitute y = 11 into equation 1 to find the value of x
x = 3y - 6
x = 3(11) - 6
x = 33 - 6
x = 27
This means that the father is presently 27 years and the son is presently 11 years.
In four years time
father = 27 + 4 = 31
son = 11 + 4 = 15
sum of their ages in four years time will be
31 + 15 = 46 years
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Assuming 5a3 equals 5a^3, and the same for everything else, you would plug in 4 for a, so 5(4)^3 - 2(4)^2 + 4 - 45, which equals 247.
First you write down all even integers that divide 20.
Those are: 2,4,10,20
Since the request is that integer is less than n, 20 cannot be the answer.
This means that greatest even integer is 10
Answer is 10.
