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astra-53 [7]
1 year ago
7

(02.02)A shape is shown on the graph:

Mathematics
1 answer:
inna [77]1 year ago
8 0

Based on the shape shown on the graph, the reflection of the shape would be b) A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, negative 2 and 4, negative 2, and 2, negative 6.

<h3>What shape is the reflection?</h3>

The coordinate grid that the shape would be reflected across is the y axis to get a reflection in the negative side of the x axis.

The first reflection would be of the point that is (2,2). It would be reflected to become (-2, 2).

The second reflection would be of point (2, 6) which would then be reflected to become (-2, 6).

Finally the third point would be of point (4, 2) which would then become (-4, 2).

In conclusion, the reflection was across the y axis.

Options include:

  • a) A coordinate grid is shown from positive 8 to negative 8 on the axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair negative 2, 2 and negative 4, 2 and negative 4, 6.
  • b) A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, negative 2 and 4, negative 2, and 2, negative 6.
  • c) A coordinate grid is shown from positive 8 to negative 8 on the axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair negative 2, 2 and negative 2, 4 and negative 6, 2.
  • d) A coordinate grid is shown from positive 8 to negative 8 on the axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, negative 2 and 2, negative 4 and 6, negative 2.

Find out more on reflection at brainly.com/question/1908648

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Step-by-step explanation:

Solve each expression given, if it has the same result, then the expressions is equivalent. Solve the given expression:

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First, change all fractions into improper fractions:

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Multiply straight across:

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