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dezoksy [38]
3 years ago
9

A group of 8 Trends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations o

f 5 friends could
possibly receive the tickets?
Mathematics
1 answer:
rjkz [21]3 years ago
8 0

Answer:

Given that there are 8 friends (5 girls and 3 boys). We have to select only 5 of them. Those 5 can be girl or boy or combination of both because no such restriction is given.

The options in this case are

All five girls go + 4 girls and 1 boy +3 girls , 2 boys+2 girls , three boys

5C5+ (5C4 * 3C1) + (5C3*3C2) + (5C2*3C3)

=1+5*3 + 10*3 +10*1 = 1+15+30+10 = 56

So the answer would be 56

If thats what your talking about.

Hopefully I was help to you!! <3

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In how many ways can the letters of the word ``COPYRIGHT'' be arranged?
PilotLPTM [1.2K]

Answer:

362,880 ways

Step-by-step explanation:

There are 9 letters so 9!

And none of them are repeated so 9!/0!

9! = 362,880

I hope this helps, and plz mark me brainliest!!

4 0
3 years ago
Charlie tosses five coins.What is the probability that all five coins will land tails up.
lesya692 [45]

Answer:

50%

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
X According to a survey, 60 sixth grade students at Madison Middle School attended a summer camp. This is 30% of the entire sixt
Liula [17]

Answer: total is 200

Step-by-step explanation:

30% = 60

10% = 60/3 = 20

100% = 200

7 0
3 years ago
Nine voltage measurements in a circuit have produced the following values: 12.09, 12.05, 11.94, 11.99, 12.12, 12.05, 12.02, 11.9
Debora [2.8K]

Answer:

we can not reject any value

Step-by-step explanation: From data we can test the highest and the lowest value to evaluate if one of these values are out of certain confidence Interval

If we established CI = 95 % then  α = 5 % and  α/2 = 0,025

From data we find the mean of the values

μ₀  = 12,03   and σ = 0,07

From z table we find z score for 0,025 is  z(c) = ± 1,96

So limits of our CI are:

12,03 + 1,96 =  13,99

12,03 - 1,96 = 10,07

And all our values are within  ( 10,07 , 13,99)

So we can not reject any value

4 0
3 years ago
Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dis
Ronch [10]
<h2><u>Complete Question: </u></h2>

Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dissimilar.

1. \frac{2}{3} $ and $ \frac{1}{3}

2. \frac{3}{4} $ and $ \frac{1}4}

3. \frac{4}{7} $ and $ \frac{7}{8}

4. \frac{2}{5} $ and $ \frac{5}{11}

5. \frac{7}{13} $ and $ \frac{7}{9}

<h2><em><u>The answers:</u></em></h2>

1. \frac{2}{3} $ and $ \frac{1}{3} - Similar (S)

2. \frac{3}{4} $ and $ \frac{1}4} - Similar (S)

3. \frac{4}{7} $ and $ \frac{7}{8} - Dissimilar (D)

4. \frac{2}{5} $ and $ \frac{5}{11} - Dissimilar (D)

5. \frac{7}{13} $ and $ \frac{7}{9} - Dissimilar (D)

Note:

  • Similar fractions have the same denominator. i.e. the bottom value of both fractions are the same.
  • Dissimilar fractions have different value as denominator, i.e. the bottom value of both fractions are not the same.

Thus:

1. \frac{2}{3} $ and $ \frac{1}{3} - They have equal denominator. <u><em>Both fractions are similar (S).</em></u>

2. \frac{3}{4} $ and $ \frac{1}4} - They have equal denominator. <em><u>Both fractions are similar (S).</u></em>

3. \frac{4}{7} $ and $ \frac{7}{8} - They have equal denominator. <em><u>Both fractions are dissimilar (D).</u></em>

4. \frac{2}{5} $ and $ \frac{5}{11} - They have equal denominator. <u><em>Both fractions are dissimilar (D).</em></u>

5. \frac{7}{13} $ and $ \frac{7}{9} - They have equal denominator. <em><u>Both fractions are dissimilar (D).</u></em>

Therefore, the fractions in <em><u>1 and 2 are similar (S)</u></em> while those in <em><u>3, 4, and 5 are dissimilar (D).</u></em>

<em><u></u></em>

Learn more here:

brainly.com/question/22099172

7 0
3 years ago
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