Answer:
X + 10
Step-by-step explanation:
or n + 10
it shows 10 more than a number
Answer:
The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.
Step-by-step explanation:
A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.
Recall that the volume for a cylinder is given by:
Substitute:
Solve for <em>h: </em>
Recall that the surface area of a cylinder is given by:
We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.
First, substitute for <em>h</em>.
Find its derivative:
Solve for its zero(s):
Hence, the radius that minimizes the surface area will be about 3.628 centimeters.
Then the height will be:
In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.
It will be rounded to 37400
Answer:
15^3−31^2+20−4
Step-by-step explanation:
Distribute
(3−2)(5^2−7+2)
3(5^2−7+2)−2(5^2−7+2)
Distribute
3(52−7+2)−2(5^2−7+2)
15^3−21^2+6−2(5^2−7x+2)
Distribute
15^3−21^2+6−2(5^2−7+2)
15^3−21^2+6−10^2+14−4
Combine like terms
15^3−21^2+6−10^2+14−4
15^3−31^2+6+14−4
Combine like terms
15^3−31^2+6+14−4
15^3−31^2+20−4
Solution
15^3−31^2+20−4
Answer:
6
Step-by-step explanation:
Point C is 6 to the left. The absolute value would be positive 6.