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Nady [450]
3 years ago
11

A spinner is divided into 5 equal sections labeled 1 to 5. If the spinner is spun 60 times, how many times can you expect the sp

inner to land on 3?
Mathematics
1 answer:
laiz [17]3 years ago
3 0

Answer:

since there are 5 equal sections it will be splitted into 1/5. There is only 1 3 on the spinner. So it is 1/3.

1/3*60=12

You can expect the spinner

to land on 3 12 times

Step-by-step explanation:

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PLEASE HELP IM OFFERING 10PTS AND BRAINLIEST ANSWER (ITS ONLY WORHT 2PTS)
wariber [46]

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(Infinity sign,-3)- I don't know how to make an infinity sign.

If it doesn't have to be in an (x,y) format, then the range = -3

Step-by-step explanation:

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6 0
3 years ago
The amount of time workers spend commuting to their jobs each day in a large metropolitan city has a mean of 70 minutes and a st
Xelga [282]

Answer:

81.85% of the workers spend between 50 and 110 commuting to work

Step-by-step explanation:

We can assume that the distribution is Normal (or approximately Normal) because we know that it is symmetric and mound-shaped.

We call X the time spend from one worker; X has distribution N(μ = 70, σ = 20). In order to make computations, we take W, the standarization of X, whose distribution is N(0,1)

W = \frac{X-μ}{σ} = \frac{X-70}{20}

The values of the cummulative distribution function of the standard normal, which we denote \phi , are tabulated. You can find those values in the attached file.

P(50 < X < 110) = P(\frac{50-70}{20} < \frac{X-70}{20} < \frac{110-70}{20}) = P(-1 < W < 2) = \\\phi(2) - \phi(-1)

Using the symmetry of the Normal density function, we have that \phi(-1) = 1-\phi(1) . Hece,

P(50 < X < 110) = \phi(2) - \phi(-1) = \phi(2) - (1-\phi(1)) = \phi(2) + \phi(1) - 1 =  \\0.9772+0.8413-1 = 0.8185

The probability for a worker to spend that time commuting is 0.8185. We conclude that 81.85% of the workers spend between 50 and 110 commuting to work.

Download pdf
7 0
3 years ago
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