Let the integers be x, x+1, and x+2
3(x+x+1)=13+4(x+2)
3(2x+1)=13+4x+8
6x+3=4x+21
2x=18
x=9
the integers are 9,10,11
First expand the brackets 18x-12=22x and then you move the 18x to the other side so 12=22x-18x 12=4x. 3=x
I can’t solve it sorry....................................................<3
Answer A seems to make the most sense to me<span />
9514 1404 393
Answer:
A. 5
Step-by-step explanation:
The base AB is twice the length of the midsegment CD.
8n +10 = 2(5n)
8n +10 = 10n . . . . . eliminate parentheses
10 = 2n . . . . . . . . . subtract 8n
n = 5 . . . . . . . . . . . divide by 2
