Answer:
13
Step-by-step explanation:
Solution :
The null and alternative hypothesis is given by


Assume that the level of significance, α = 0.05
The t-test statistics is, t = 1.484
Degree of freedom :
df = n - 1
= 14 - 1
= 13
The P-value is given by
P-value = 2P (T>|t|)
= 2P(T>|1.484|)
= 2P(T>1.484)
= 2(=T.DIST.RT(1.484,13))
= 0.05
Answer: The habitat quality score will be normally distributed if at least 50% of the total sites are captured
Step-by-step explanation:
For this case we have that by definition of trigonometric relations that the sine of an angle is equal to the opposite leg to the angle on the hypotenuse. That is to say:

Clearing the value of "a":

Rounding off we have:
17.7
Answer:
Option B
Answer:
vjfduydyhf uusuffvv iitsfvn hi9fecv uurwsdffyxch gui9