In ΔJKL
s = JK+KL+LJ/2
= 25+7+21/2
= 28
then,
ΔJKL = √[s(s-a)(s-b)(s-c)]
= √[28(28-25)(28-24)(28-7)
= √(28×3×4×21)
= √(7056
= 84cm²
Again,
ΔJKL = 1/2×JL×LK×∠L
or, 84 = 1/2×24×7×sin x°
or, 84/168 = sin x°
or, 1/2 = sin x°
or sin 30° = sin x°
or x° = 30°
At last,
∠K+∠L+∠J = 180° (sum of angle of triangle)
or, ∠K+30°+90° = 180°
or, ∠K = 180°- 120°
or, ∠K = 60°
Answer: Multiply (60 − 2x) and (2 + 0.25x) to create the equation y = -0.5x2 + 11x + 120
We know that David wants to increase the price per cup to increase his revenue. He found out that for every $0.25 grows( increase), x, in the price for each cup.
In the event of a price increase, 2 cups remain unsold, and doubling the cups is still not sold. Then the numbers are sold (60-2x). Depending on the choice:
Revenue= (60 -2x)(2 +0.25x)
60·2 +60·0.25x -2x·2 -2x·0.25x
= -0.5x² +11x +120
Answer:
Given:
To Find:
Value of f(x) when x = -3
Step-by-step explanation:
Given a square ABCD and an equilateral triangle
DPC and given a chart with which
Jim is using to prove that triangle APD is
congruent to triangle BPC.
From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.
Therefore, the justification to complete Jim's proof is "SAS postulate".
To find the surface area you will need to find the areas of all 6 surfaces. The 2 bases are trapezoids and the 4 lateral faces are rectangles.
This shape is a trapezoidal prism.
Trapezoid 1:
A = 1/2h(b1 + b2)
1/2 x 8(8 + 12)
A = 80 square inches
Trapezoid 2 = 80 square inches
Rectangle 1
A=bh
8 x 8= 64 square inches
Rectangle 2
A= 64 square inches
Rectangle 3
A = 8 x 9
A = 72 square inches
Rectangle 4
A = 12 x 8
A = 96 square inches
S.A.= 96+72+64+64+80+80
S.A.=456 square inches
