The content of care package would be a board game and several snack packs.
Given is the weight of board game = 4 pounds.
The weight of one snack pack =
The total weight would be less than 25 pounds.
Solving for part A :
Let 'x' represents the number of snack packs.
So the weight of all snack packs would be 0.5x pounds.
Now weight of care pack = weight of board game + weight of all snack packs.
weight of care pack = 4 + 0.5x
But total weight must be less than 25 pounds.
So the inequality would be: 4 + 0.5x < 25
Solving for part B :
Solving the inequality 4 + 0.5x < 25
⇒ 4 + 0.5x - 4 < 25 - 4
⇒ 0.5x < 21
⇒ x < 42
Solving for part C :
Since x < 42 and x is an integer number, so x = 41.
She can include maximum of 41 snack packs in the care package.
Answer:
V= 14.13
Step-by-step explanation:
Information needed:
V= 4/3
r^3
= 3.14
r= 3/2
Solve:
V= 4/3
r^3
V= 4/3(3.14)(3/2)^3
V= 4/3(3.14)(27/8)
V= 14.13
The answer is 50. You add all of the numbers in the data set, and divide it by the number of numbers in the data set. the sum of all of the numbers is 350, divide that by 7( the amount of numbers in the data set) and you get 50
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332