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Genrish500 [490]
3 years ago
14

There is 12/15 of a pizza left how many 3/10 pieces can be made from the leftover pizza

Mathematics
1 answer:
LiRa [457]3 years ago
3 0
If you put it in the calculator as 12÷15-3÷10, you get 0.5. you could simplify, but you might get a different answer.
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Rolling a 6-sided die and counting the number of each outcome that occurs is a bionomial random variable. True or False? Which o
il63 [147K]

Answer:

False.

Step-by-step explanation:

This is NOT an example of a binomial random variable, because a binomial random variable can only have TWO possible outcomes: success or failure. In the case of rolling a die, there are SIX possible outcomes: 1, 2, 3, 4, 5, or 6.

So, rolling a 6-sided die and counting the number of each outcome that occurs is NOT a binomial random variable.

Hope this helps!

7 0
3 years ago
A theater wants to build movable steps that they can use to go on and off the stage. They want the steps to have enough space in
GrogVix [38]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Is this correct? I'm really confused xD
denpristay [2]
Yes, your current answer is correct. Divide each term by the divisor. 
4 0
3 years ago
Find the solution set of the inequality:<br> -3x + 8 &lt; 15−3x+8&lt;15
makkiz [27]

Answer:

x=(8/3, infinity)

Step-by-step explanation:

-3x+8<15-3x+8

-3x+8<-3x+23

8<23

15-3x+8<15

23-3x<15

-3x<-8

x>8/3

Therefore, x=(8/3, infinity)

3 0
2 years ago
The number of milligrams of a certain medicine a veterinarian gives to a dog varies directly with the weight of the dog. If the
Andre45 [30]

Answer:

Step-by-step explanation:

A direct variation equation is of the form

y = kx,

where, in words, it reads "y varies directly with x" or "y varies directly as x". In order to use this as a model, we have to have enough information to solve for k, the constant of variation. The constant of variation is kind of like the slope in a straight line. It rises or falls at a steady level; it is the rate of change.

We have that a vet gives a dose of three-fifths mg to a 30 pound dog. If the dose varies directly with the weight of the dog, then our equation is

d = kw and we need to find k in order to have the model for dosing the animals.

\frac{3}{5} =k(30)

Divide both sides by 1/30 to get k alone.

(\frac{1}{30})(\frac{3}{5})=k and

k=\frac{1}{50}

Our model then is

d=\frac{1}{50}w

This means that for every pound of weight, the dog will get one-fiftieth of a mg of medicine.

7 0
3 years ago
Read 2 more answers
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