The amount of money that Phyllis invested at each given rate of 4 and 6 percent is = $394.57 and $591.86 respectively.
<h3>Calculation of the total capital invested</h3>
The time the investment lasted= 12 years.
Simple interest = 1579.05 - 800= $779.05
The principal capital= $800
Rate of the both capital invested;
= SI × 100/P ×T
= 779.05 × 100/800 × 12
= 77,905/9600
= 8.11%
To find the amount of money that Phyllis invested at each given rate,
Rate 1 = 4/8.11× 800
= 3200/8.11
= $394.57
Rate 2 = 6/8.11× 800
= 4800/8.11
= $591.86
The amount of money that Phyllis invested at each given rate of 4 and 6 percent is = $394.57 and $591.86 respectively.
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Answer:
7° and 83°
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
← factor both numerator and denominator
= 
← cancel common factor (1 - 2b) on numerator/denominator
= 
← cancel 6 and 3 by 3
=
Answer:
slope = 2
Step-by-step explanation:
Calculate the slope m using the slope formula
m = 
with (x₁, y₁ ) = (2, 3) and (x₂, y₂ ) = (4, 7)
m = 
= 
= 2
Answer:
.
Step-by-step explanation:
A point of the form 
belongs to the graph of this function, 
, if and only if the equation of this function holds after substituting in 
and 
.
The question states that the point 
belongs to the graph of this function. Thus, the equation of this function, , should hold after substituting in 
and 
:
.
.
Solve this equation for the constant 
:
.
Thus, .
