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enyata [817]
3 years ago
11

A student solved z + (-0.72) = -2.5 for z using the following steps.

Mathematics
2 answers:
prisoha [69]3 years ago
6 0

The student's error was in first step where he added -0.72 instead of 0.72

Step-by-step explanation:

Given equation;

z + (-0.72) = -2.5

When solving for z, eliminate the other numbers from one side.

Step 1: z + (−0.72) + (−0.72) = −2.5 + (−0.72)

In this step, the student should have added 0.72 because -0.72 was already present in the equation and to eliminate it, he should have add same number with opposite sign.

According to this Step, -0.72 and -0.72 would have been added, because according to mathematics, two numbers with minus sign are added and the sign remains same.

The student's error was in first step where he added -0.72 instead of 0.72

Keywords: addition, subtraction

Learn more about addition at:

  • brainly.com/question/10978510
  • brainly.com/question/11007026

#LearnwithBrainly

Elza [17]3 years ago
4 0

Answer:

To solve, you must use the inverse operation. In step 1, -0.72 should have been subtracted from both sides, not added. Otherwise, 0.72 should have been added to both sides, not -0.72.

Step-by-step explanation:

I got it wrong for y'all LOL

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"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

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