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yuradex [85]
3 years ago
7

Write a ratio to express the number of people who preferred WANR to those who preferred WCLM.

Mathematics
2 answers:
Anika [276]3 years ago
6 0
WANR - 22%
WCLM - 24%
WWCN - 41%
WKOD - 13%

The ratio of WANR to WCLM is 22:24  OR 11:12
Ratio of WANR to the whole is 22:100 OR 11:50
Ratio of WCLM to the whole is 24:100 OR 12:50 


DENIUS [597]3 years ago
5 0

Answer: 11/12 is the ratio to express  the number of people who preferred WANR to those who preferred WCLM.

Step-by-step explanation:

Let the total number of people= x

So, According to the given diagram,

The number of people who preferred WANR = 22% of x

While, The number of people who preferred WCLM = 24% of x

Therefore, The number of people who preferred WANR/The number of people who preferred WCLM = 22% of x / 24% of x

= \frac{22/100\times x}{24/100\times x} = \frac{22}{24} =\frac{11}{12}

Which is the required answer.


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Answer:

500

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There are 4 people at a party. If each person must shake hands with every
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Answer: 6

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3 years ago
1. determine if the functions are inverse functions
kirill115 [55]

Answer:

<u>Question 1</u>

The function f(x) = x + 6 is one-to-one, so it does have an inverse.

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<u>Question 2</u>

The function f(x) = -3x -9 is one-to-one, so it does have an inverse.

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Replace x with f^{-1}(x) and y with x:

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Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno
spin [16.1K]
The other endpoint is (1, -17).

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m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Using our midpoint and endpoint, we have:
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For the first equation (to find the x-coordinate) we will multiply both sides by 2:
6\times2=\frac{11+x_2}{2}\times 2&#10;\\&#10;\\12=11+x_2

Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
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-11\times2=\frac{-5+y_2}{2}\times 2&#10;\\&#10;\\-22=-5+y_2

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4 0
3 years ago
The diagram shows a logo​
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Answer/Step-by-step explanation:

✔️Find EC using Cosine Rule:

EC² = DC² + DE² - 2*DC*DE*cos(D)

EC² = 27² + 14² - 2*27*14*cos(32)

EC² = 925 - 756*cos(32)

EC² = 283.875639

EC = √283.875639

EC = 16.85 cm

✔️Find the area of ∆DCE:

Area = ½*14*27*sin(32)

Area of ∆DCE = 100.15 cm²

✔️Since ∆DCE and ∆ABE are congruent, therefore,

Area of ∆ABE = 100.15 cm²

✔️Find the area of the sector:

Area of sector = 105/360*π*16.85²

Area = 260.16 cm² (nearest tenth)

✔️Therefore,

Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)

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