The number of ways for which she could pick four colours if green must be one of them is; 10 ways.
<h3>How many ways can she picks four colours if green must be there?</h3>
It follows from the task that there are 6 colours in total that she could pick from.
Hence, since she needs four colours with green being one of them, it follows that she only has 3 colours to pick from 5.
Hence, the numbers of possible combinations is; 5C3 = 10 ways.
Read more on combinations;
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Answer: 3x^+13x-56
Steps
1). Multiply the parentheses
(X+7)(3x-8)
=X x 3x -8x+7 x 3x -7 x 8
2). Multiply
3x^-8x + 21x - 56
3). Do like terms
3x^+13x - 56
4). Solution
[3x^+13x - 56]
-HOPE THAT HELPEDED <3
Answer:
1. 7
2. 54÷2=27
only this I know please put brainlest
(B) x = 40
Step-by-step explanation:
4x + 20 = 180
4x = 160
x = 40
There are 3 bracelets.
The first bracelet can occupy a position in 3 ways.
The second bracelet can occupy the remaining 2 positions in 2 ways.
The third bracelet can occupy the remaining position in 1 way.
The total number combinations is
3*2*1 = 6
Answer: 6
