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TEA [102]
3 years ago
14

Please help, I can't figure out how to set this up. There's supposed to be 2 equations.

Mathematics
1 answer:
Valentin [98]3 years ago
7 0

Hello from MrBillDoesMath

Answer:     + 4/7,   6 (13/14)

Discussion:

Let L be the larger of the two numbers and S the smaller of the two. Then the first sentence translates into this:


-6L - L = -4  =>

-7L = -4        =>          (divide both sides by -7)

L = - (-4)/(-7) = + 4/7       (*)


The second sentence translates to

2 (L + S) = 15  =>               (divide both sides by 2)

(L +S) = 15/2  =>                (subtract L from each side)

S = 15/2 - L = 15/2 - 4/7    (using (*) above)

So

S = 15*7/(2*7) - (4*2)/(7*2)       (combine over common denominator of 14)

S = 105/14 - 8/14 = 97/14 = 6 13/14

Something is crazy here!    While 2(L +S) = 15  -- check it out -- our larger number L ( =4/7) is actually smaller than the S number (6 13/14)!  Maybe I should have called them Y and X, respectively, as you suggested!

Thank you,

Mr. B


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3 years ago
The probabilty that a student owns a car is 0.65 the porbability that a student owns a compuer is 0.82 the probability that a st
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Question:  The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

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(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B)  = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

Pr(not-A and not-B) = 0.08

Hence the probability that a student selected randomly does not own a car or a computer is 0.08

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