First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2
4t+ 14= 6t/5+ 7
⇒ 4t+ 14= 6/5t+ 7
⇒ 4t -6/5t= 7 -14
⇒ (4 -6/5)t= -7 (distributive property)
⇒ 14/5t= -7
⇒ t= -7/ (14/5)
⇒ t= -5/2
⇒ t= -2.5
Final answer: t= -2.5~
Answer:
D. X=-3, y=4
Step-by-step explanation:
-2x+3y=18 equation 1
x=-y+1 equation 2
-2(-y+1)+3y=18 replace x value of equation 2 into equation 1
2y-2+3y=18
5y=20
y=4
solve for x by replacing y value into either equation.
x=-y+1
x=-4+1
x=-3
Answer:
From the attached graphic, we can see:
(SP + PR) * PR = (WQ + QR) * QR
SP * PR + PR^2 = WQ * QR + QR^2
4 SP + 4*4 = 8 * 5 + 25
4 SP + 16 = 65
4 SP = 49
SP = 49 / 4
SP = 12.25
Step-by-step explanation:
Answer:
C) 180
Step-by-step explanation:
I hope this helps
Good luck ;)
